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May 2025 Section II

0/46 marks

2025 · 7 questions · 40 parts · 46 marks

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1(A)(i)1(A)(ii)1(B)(i)1(B)(ii)1(C)1(D)1(E)(i)1(E)(ii)1(E)(iii)1(F)2(A)2(B)(i)2(B)(ii)2(B)(iii)2(C)2(D)3(A)3(B)(i)3(B)(ii)3(C)3(D)3(E)3(F)(i)3(F)(ii)4(A)4(B)4(C)(i)4(C)(ii)5(A)5(B)5(C)5(D)6(A)6(B)6(C)6(D)7(A)7(B)(i)7(B)(ii)7(C)
Context for question 7
Answer the following questions about the glycolate ion, C2​H3​O3−​, which acts as a base in aqueous solution. A Lewis diagram for the ion is provided.
When the glycolate ion reacts with water, it forms glycolic acid, HC2​H3​O3​, according to the following equation. The Kb​ expression for the reaction is provided.
C2​H3​O3−​(aq)+H2​O(l)⇌HC2​H3​O3​(aq)+OH−(aq)
Kb​=[C2​H3​O3−​][HC2​H3​O3​][OH−]​
7(A)Acids, Bases and Salts: Properties and TheoriesEasy1 mark
On the Lewis diagram in part A, circle the atom that accepts the proton when the glycolate ion reacts with water.
Context for 7(B)
At 25∘C, a 2.5 M solution of glycolate is found to have [OH−] = 1.3×10−5 M.
7(B)(i)pH, Weak Acids, Buffers and Titration CurvesEasy1 mark
Calculate the value of Kb​ for the glycolate ion.
7(B)(ii)pH, Weak Acids, Buffers and Titration CurvesEasy1 mark
Using your answer to part B(i), calculate the value of Ka​ for glycolic acid at 25∘C.
Context for 7(C)
Glycolic acid can be produced from the hydrolysis of methyl glycolate, C3​H6​O3​. A proposed mechanism for the reaction is given.
Step 1: C3​H6​O3​+H3​O+⇌C2​H5​O3+​+CH3​OH
Step 2: C2​H5​O3+​+H2​O⇌HC2​H3​O3​+H3​O+
Overall: C3​H6​O3​+H2​O⇌HC2​H3​O3​+CH3​OH
7(C)Catalysis, Reaction Profiles and Enzyme KineticsMedium1 mark
A student claims that H3​O+ is a catalyst for the reaction. Do you agree or disagree? Justify your answer based on the mechanism given.
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