White phosphorus is composed of P4 molecules with a tetrahedral structure, as shown in the diagram on the left. Each P atom is bonded to the other three P atoms by single bonds, as shown in the incomplete Lewis diagram on the right.
3(A)Covalent Bonding, Lewis Structures and Molecular ShapeEasy1 mark
In the box in part A, complete the Lewis diagram for P4 by drawing the nonbonding electrons.
Context for 3(B)
The reaction of white phosphorus with oxygen to form P4O10(s) is thermodynamically favorable at 298 K. The reaction is represented by equation 1.
Equation 1: P4(s)+5O2(g)→P4O10(s)
3(B)(i)Entropy, Gibbs Energy and FeasibilityEasy1 mark
The entropy change of the reaction, ΔSrxn∘, is negative. Using particle-level reasoning, explain why the entropy decreases as the reaction progresses.
3(B)(ii)Entropy, Gibbs Energy and FeasibilityMedium1 mark
The enthalpy change of the reaction, ΔHrxn∘, is also negative. A student claims that the favorability of the reaction is driven by enthalpy and not by entropy. Is the student's claim correct? Justify your answer by using the relationship between ΔGrxn∘, ΔHrxn∘, and ΔSrxn∘.
Context for 3(C)
P4O10(s) reacts exothermically with water to form phosphoric acid, as represented by equation 2.
Equation 2: P4O10(s)+6H2O(l)→4H3PO4(aq)
A chemist uses a calorimetry experiment to determine the enthalpy change for the reaction, as represented by the following diagram.
The chemist carries out the calorimetry experiment and records the following information.
Quantity
Value
Mass of P4O10
0.100 g
Mass of H2O
100.0 g
Initial temperature
22.00 ∘C
Final temperature
22.38 ∘C
Molar mass of P4O10
283.9 g/mol
Specific heat of H2O
4.18 J/(g·∘C)
3(C)Enthalpy Changes, Calorimetry and Hess's LawMedium3 marks
i. Calculate the amount of heat, q, released during the experiment, in kJ. Assume that the specific heat of the solution is the same as that of water.
ii. Calculate the value of ΔHrxn∘ for equation 2 in kJ/molrxn. Include the sign in your answer.
3(D)Enthalpy Changes, Calorimetry and Hess's LawMedium1 mark
The chemist weighed out 0.100 g of P4O10 and 100.0 g of H2O to perform a second trial. In the second trial, some of the solid P4O10 stuck to the weighing paper and was not transferred to the calorimeter. Given that P4O10 is the limiting reactant, would ΔHrxn∘ for the second trial be greater than, less than, or equal to the value in the first trial? Justify your answer.
Context for 3(E)
P4(s) also reacts readily with Cl2(g) to produce phosphorus trichloride, PCl3(g), which in turn reacts with Cl2(g) in an equilibrium process to produce PCl5(g). The reactions are represented by equations 3 and 4.
Equation 3: P4(s)+6Cl2(g)→4PCl3(g) with ΔHrxn,1∘=−1148 kJ/mol
Equation 4: PCl3(g)+Cl2(g)⇌PCl5(g) with ΔHrxn,2∘=−88 kJ/mol
3(E)Enthalpy Changes, Calorimetry and Hess's LawEasy1 mark
Calculate the standard enthalpy of formation of PCl5(g) represented by equation 5.
Equation 5: 41P4(s)+25Cl2(g)→PCl5(g) with ΔHf∘=?
Context for 3(F)
Equation 4 for the reaction that occurs is shown.
Equation 4: PCl3(g)+Cl2(g)⇌PCl5(g) with ΔHrxn,2∘=−88 kJ/mol
The following particle-level diagram represents the contents of the vessel in an equilibrium mixture at 546 K involving equation 4.
3(F)(i)Chemical Equilibrium: Le Chatelier, Kc, Kp and CalculationsEasy1 mark
If each particle in the diagram represents a partial pressure of 1.00 atm, what is the value of Kp for the equilibrium mixture at 546 K?
3(F)(ii)Chemical Equilibrium: Le Chatelier, Kc, Kp and CalculationsMedium1 mark
Does the value of Kp increase, decrease, or remain the same when the temperature is increased to 596 K? Justify your answer based on ΔHrxn,2∘.