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May 2025 Section II

0/54 marks

2025 · 6 questions · 24 parts · 54 marks

0Correct0Partial0Wrong24Unattempted
1(A)1(B)1(C)1(D)2(A)2(B)2(C)2(D)3(A)3(B)3(C)3(D)4(A)4(B)4(C)4(D)5(A)5(B)5(C)5(D)6(A)6(B)6(C)6(D)
Context for question 6
Consider the curve G defined by the equation y3−y2−y+41​x2=0.
6(A)Implicit, Parametric and Vector DifferentiationEasy2 marks
Show that dxdy​=2(3y2−2y−1)−x​.
6(B)Tangents, Normals and Linear ApproximationEasy2 marks
There is a point P on the curve G near (2,−1) with x-coordinate 1.6. Use the line tangent to the curve at (2,−1) to approximate the y-coordinate of point P. Show the work that leads to your answer.
6(C)Tangents, Normals and Linear ApproximationEasy2 marks
For x>0 and y>0, there is a point S on the curve G at which the line tangent to the curve at that point is vertical. Find the y-coordinate of point S. Show the work that leads to your answer.
6(D)Derivatives of Exponential, Logarithmic, Trigonometric and Inverse FunctionsMedium3 marks
A particle moves along the curve H defined by the equation 2xy+lny=8. At the instant when the particle is at the point (4,1), dtdx​=3. Find dtdy​ at that instant. Show the work that leads to your answer.
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